AXIS OF SYMMETRY 1

Find the axis of symmetry for F(x) = 11x² + 40x + 8

Solution

a=11, b=40

Axis of symmetry = -b/2a

                                 =  -(40)

                                   2 x 11

                                =    -40

                                       22

                                =   -20

                                     11

Hence the axis of symmetry is ^-20/11

TRY THIS...............

Find the axis of symmetry for F(x) = 5x² + 70x + 1