If Logb8 – log 0.00001
= 8; find b
Solution
Logb8 – log 0.001
= 6; [0.00001=10-5 ]
Logb8 – log 10-3 =
6
Logb8 – (-3log 10) =
6
Logb8 + 3log 10 =
6 [remember log 10
= 1]
Logb8 + (3 x 1) = 6
Logb8 + 3 = 6
Logb8 = 6 - 3
Logb8 =
3 [Change
it into exponential notation]
8 = b3
23 = b3 [ bases are same on both sides, so they cancel out ]
b = 2
Hence b = 2
TRY THIS..............
If Loga729 – log 0.00001
= 11; find a
No comments:
Post a Comment