LOGARITHMS 16

Evaluate Log₂(512 x 32).

Solution

= Log₂(512 x 32)

= Log₂512 +  Log₂32          (applying the product rule)

= Log₂2⁹ +  Log₂2⁵             ( 512= 2⁹ and 32=2⁵ )

= 9Log₂2 +  5Log₂2       ( remember  Log_aa^c = cLog_aa )

= (9 x 1) +  (5 x 1)          ( remember  Log_aa = 1 )

= 9 + 5

= 14

hence Log₂(128 x 512) = 12 

TRY THIS...............

Evaluate Log₂(256 x 128).