Find the maximum value of the quadratic
equation:3-2t-8t2.
Solution
a=-8, b=-2, c=3
Maximum = 4ac-b2
4a
Maximum = (4 x -8 x 3) - (-2)2
4(-8)
Maximum = (-96)- 4
32
Maximum= -100
32
Maximum = -25
8
Hence
maximum value is -25/8
TRY THIS………………………………..
NECTA 2003 QN. 10c
No comments:
Post a Comment