Find
the maximum value of the quadratic equation:3-2t-8t2.
Solution
a=-8,
b=-2, c=3
Maximum
= 4ac-b2
4a
Maximum
= (4 x -8 x 3) - (-2)2
4(-8)
Maximum
= (-96)- 4
32
Maximum=
-100
32
Maximum
= -25
8
Hence maximum value is -25/8
TRY
THIS………………………………..
NECTA 2003 QN. 10c
Find
the maximum value of the quadratic equation:3+30t-5t2.
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