If n(A)= 55 , n(B)= 90 and n(AuB)= 136,
find n(AnB).
Solution
n(AuB) = n(A) + n(B) - n(AnB)
136 = 55 + 90 - n(AnB)
136 = 145 - n(AnB)
136 - 145 = - n(AnB)
-9 = -n(AnB)
n(AnB) = 9 [after dividing by -1 both
sides]
Hence n(AnB) = 9 answer
TRY THIS………….
If n(A)= 89 , n(B)= 92 and n(AuB)= 137,
find n(AnB).
Sets is a very interesting topic in mathematics. It is normally covered in Form II, although a form IV student can find it as a revision for NECTA preparations. ore examples on this topic have been posted and more newer examples will be added as well. Hope you enjoy.
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