Find the sum of the
1st 18 terms of the following arithmetic progression: 5+11+17+…………………
Solution
d=6, A1 =
5,n=18
Sn = n[2A1
+ (n-1)d]
2
S18 = 18[2(5)
+ (18-1)d]
2
S18 = 9[10
+ 17d]
S18 = 9[10
+ 17(6)] since d=6
S18 = 9[10
+ 102]
S18 = 9 x 112
S18 = 1008
Therefore the sum of 1st 18 terms is 1008.
TRY
THIS............
Find the sum of the
1st 12 terms of the following arithmetic progression: 6+10+14+…………………
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