Find a linear function f(x) with
gradient -1 which is such that f(5)=12.
Solution.
m=-1, points = [5,12] and [x, f(x)]
m = (y2-y1)/x2-x1
-1 = [f(x) – 12]/x-5
f(x)-12=-1(x-5) [after cross
multiply]
f(x)-12=-x+50
f(x)=-x+50+12
f(x)=-x+62
So a linear
function is f(x) = -x+62.
TRY THIS……….
Give out a linear function f(x) with
gradient 8 and f(2)=13
No comments:
Post a Comment