When
a die is tossed, find the probability of having a multiple of 2 number.
Solution
n(E)
= {2,4,6}=3; n(S) ={1,2,3,4,5,6}=6;
P(E)=
n(E)
n(S)
P(E)=
3 1
P(E)=
1
2
Hence probability of getting
a prime number is 1/2
TRY
THIS……………………………………
When
a die is tossed, find the probability of having a multiple of 3.
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