If log 2= 0.3010; find
the value of log 2500 without using tables.
solution
log2500=log(10,000÷ 4)
=log10,000 - log4
=log104 –
log22
=4log10 – 2log2
=(4x1) – 2(0.3010)
=4– 2(0.3010)
=4 – 0.6020
=3.398
Hence log2500=3.398
TRY THIS……………
If log 2= 0.3010; find the value of log 250,000
without using tables.
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