MATHEMATICS PROBLEM SOLVER

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Thursday, 10 November 2016

ARITHMETIC PROGRESSION 2

The 1st term of an A.P. is 80 and the common difference is 34. Find the 10th term.

Solution

A₁= 80, d = 34

A_n = A₁ + (n-1)d

A₁₀ = A₁ + (10-1)d

A₁₀ = A₁ + 9d

A₁₀ = 80 + (9x34) [after substituting A₁= 80, d = 34 as given above]

∴ A₁₀ = 80 + 306

A₁₀ = 386

Hence the 10th term is 386.

TRY THIS……………

The 1st term of an A.P. is 46 and the common difference is 38. Find the 12th term.

MATHEMATICS PROBLEM SOLVER

Thursday, 10 November 2016

ARITHMETIC PROGRESSION 2

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