Thursday, 10 November 2016

LOGARITHMS 5


Evaluate Log2(2048 x 128).

Solution

= Log2(2048 x 128)

= Log22048 +  Log2128          (applying the product rule)

= Log2211 +  Log227             (2048= 211 and 128=27 )

= 11Log22 +  7Log22       (remember  Logaac = cLogaa)

= (11 x 1) +  (7 x 1)          (remember  Logaa = 1)

= 11 + 7

= 18

hence Log2(2048 x 128) = 18  .

TRY THIS………………


Evaluate Log2(8192 x 256). 


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