Find
a linear function f(x) with gradient -20 which is such that f(5)=12.
Solution.
m=-20,
points = [5,12] and [x, f(x)]
m
= y2-y1/x2-x1
-20 = f(x) – 12/x-5
f(x)-12=-20(x-5)
[after cross multiply]
f(x)-12=-20x+100
f(x)=-10x+100+12
f(x)=-10x+112
Hence A linear function is f(x) = -10x+112.
TRY
THIS……….
Give
out a linear function f(x) with gradient
11 and f(5)=16.
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