LOGARITHMS J6

 

If log₈(3x + 19)=2; find x

 

   Solution

 

Log₈(3x + 19)=2

 

 (3x + 19)=8²   [changing logarithmic form into exponential form]

                      

 3x + 19=64

 

 

3x = 64 – 19

 

3x =  45

 

 

3x =  45         [dividing by 3 both sides]

3        3

 

x = 15

 

Hence x = 15

 

 

TRY THIS...............

 

 

If log₃(3u - 39) = 5; find u.