Saturday 8 February 2014

LOGARITHMS B22

Evaluate Log2(64 x 256).

Solution

= Log2(64 x 256)

= Log264 +  Log2256          (applying the product rule)

= Log226 +  Log228             ( 64= 26 and 256=28 by prime factorization)

= 6Log22 +  8Log22       ( remember  Logaac = cLogaa )

= (6 x 1) +  (8 x 1)          ( remember  Logaa = 1 )

= 6 + 8

= 14

Hence Log2(64 x 256) = 18


TRY THIS.......


Evaluate Log2(2048 x 256).


No comments:

Post a Comment