SETS B1

 

If n(A)= 83 , n(B)= 93 and n(AuB)= 130, find n(AnB).

Solution

n(AuB) = n(A) + n(B) - n(AnB)

130 = 83 + 93 - n(AnB)

130 = 176 - n(AnB)

130 - 176 = - n(AnB)

-46 = -n(AnB)

n(AnB) = 41       [after dividing by -1 both sides]

Hence n(AnB) = 41 answer

TRY THIS………….

If n(A)= 92 , n(B)= 98 and n(AuB)= 160, find n(AnB).