LOGARITHMS B1

 

Evaluate Log1,000,000 +  log 0.00001 + log₃243

 

Solution

 

= Log1,000,000 +  log 0.001 + log₃243

 = Log10⁶ +  log 10^-5 + log₃3⁵

 = 6Log10 +  (-5log 10) + (5log₃3)    [since log_aaⁿ  = nlog_aa]

 = (6x1) + (-5x1) + (5x1)             [since log_aa = 1]

 = 6 + (-5) + (5)

 = 6 

Hence Log1,000,000 +  log 0.00001 + log₃243 = 6

 

TRY THIS...............................

 

Evaluate Log10,000 +  log 0.01 + log₃729