If f(x) = x4 + kx2 + 6x + 7 has
a remainder of 91 when divided by x+2; find k.
solution
f(x) = x4 + kx2 + 6x + 7
x + 2 = 0
x = -2
f(x) = (-2)4 + k(-2)2 + 6(-2) +
7 = 91
16 + 4k + (-12) + 7 = 91
16 + 4k - 12 + 7 = 91
16 + 4k - 5 = 91
4k + 16 - 5 = 91
4k + 11= 91
4k = 91 - 11
4k = 80
4k = 80
4 4
k = 20
hence k = 20
TRY THIS......................
If f(x) = x4 - hx2 + 2x - 13 has
a remainder of 16 when divided by x-3; find h.
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