Friday, 3 September 2021

LOGARITHMS B3

 

If Log(30x-110/5+x) = 1. Find x.

Solution

Log(30x-110/5+x) = 1.

Log10(30x-110/5+x) = 1.

 30x-110 = 101. After changing into exponential form

   5+x

 

30x-110 = 10    since [101=10]

   5+x

 

30x-110 = 10(5+x)    after cross multiply

  

30x-110 = 50+10x

 

30x-10x = 50+110 [collecting like terms]

 

20x = 160

 

x=8  [after dividing by 20 both sides]

Hence x=8.

TRY THIS……………

If Log(30x-50/7+x) = 1. Find x.



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