Find the
slope of a line which passes through (-3, -4) and (8,-13)
Solution
x1 =
-3, y1 =-4, x2 = 8, y2 =
-13
m = y2
–y1
x2 – x1
m =
-13 –(-4)
8 –(-3)
m = -13 + 4 [Since -(-4) = +4, and -(-3) = +3]
8 + 3
m =
- 9
11
Hence the slope is -9/11
TRY
THIS...................................
Find the slope of a line that passes through (-11, -2)
and (4,-10)
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