Find the
maximum value of the quadratic equation:3-2t-8t2.
Solution
a=-8,
b=-2, c=3
Maximum = 4ac-b2
4a
Maximum = (4
x -8 x 3) - (-2)2
4(-8)
Maximum = (-96)-
4
-32
Maximum= -100
-32
Maximum = 25
8
Hence
maximum value is 25/8
TRY
THIS………………………………..
NECTA
2003 QN. 10c
Find the
maximum value of the quadratic equation:3+30t-5t2.
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