WORD PROBLEMS 1

Ana, Joy and Fred shared 800 sweets such that Ana got 10 sweets less than Joy while Fred got three as much as what Ana got. Find those given to Fred.

Solution

The starting point is Joy. Let the sweets given to Joy be x. See the table below:

ANA	JOY	FRED
x-10	x	3(x-10)=3x-30

  

Then;

ANA + JOY + FRED = 800

x-10 + x + 3x-30 = 800

x + x + 3x - 30 - 10 = 800

5x - 40 = 800

5x = 800 + 40

5x = 840

5x = 840

5       5

x = 168

The sweets given to Fred

= 3x – 30

= 3(168) – 30

= 504 – 30

=474

Hence Fred got 474 sweets.

TRY THIS………………………

Kemi, Roy and Isaya shared 610 sweets such that Kemi got 10 sweets less than Roy while Isaya got four as much as what Kemi got. Find those given to Kemi.   [100 answer]