Wednesday, 27 December 2017

LOGARITHMS 9


Evaluate Log2(1024 x 8).

Solution

= Log2(1024 x 8)

= Log21024 +  Log28          (applying the product rule)

= Log2210 +  Log223             ( 1024= 210 and 8=23 )

= 10Log22 +  3Log22       ( remember  Logaac = cLogaa )

= (10 x 1) +  (3 x 1)          ( remember  Logaa = 1 )

= 10 + 3

= 13

hence Log2(1024 x 8) = 13 

TRY THIS...............


Evaluate Log2(1024 x 64). 

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