Find a linear function f(x) with
gradient -6 which is such that f(5)=16.
Solution.
m=-6, points = [5,16] and [x, f(x)]
m = y2-y1/x2-x1
-6 = [f(x) – 16]/x-5
f(x)-16=-6(x-5) [after cross
multiplying]
f(x)-16=-6x+30
f(x)=-6x+30+16
f(x)=-6x+46
A linear function is f(x) = -6x +
46.
TRY THIS……….
Give out a linear function f(x) with
gradient -11 and f(2)=18
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