QUADRATICS 1

Given that one of the roots of the equation 5x² + m(x+1) + 5 = 0 is 7, find m.

Solution

Substitute x=7, in the above equation.

5(7)² + m(7+1) + 5 = 0

(5x49) + (m x 8) + 5 = 0

245 + 8m + 5 = 0

8m + 5 = -245

8m = -245 - 5

8m = -250

8m = -250

8         8

m=^-125/8

Hence m=^-125/8

TRY THIS…………………………..

Given that one of the roots of the equation 3x² + e(x-2) + 3 = 0 is 4, find e.