QUADRATICS 2

Find the maximum value of the quadratic equation:3-2t-10t².

Solution

a=-10, b=-2, c=3

Maximum = 4ac-b²

                        4a

Maximum = (4 x -10 x 3) - (-2)²

                          4(-10)

Maximum = (-120)- 4

                         -40

Maximum=  -124

                      40

Maximum = -31

                     10

Hence maximum value is -31/10

TRY THIS………………………………..

Find the maximum value of the quadratic equation:7+28t-6t².