Friday, 4 November 2016

FUNCTIONS 3


Find the maximum value of the quadratic equation:3-6t+8t2.

Solution

a=8, b=-6, c=3

Maximum = 4ac-b2
                       4a

Maximum = (4x8x3)-(-6)2
                         4(8)

Maximum = (96)- 36
                        32

Maximum= 60
                    32

Maximum = 15
                     8
Hence maximum value is 15/8

TRY THIS………………………………..

NECTA  2003 QN. 10c

Find the maximum value of the quadratic equation:3+30t-5t2.


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