Find the maximum value of the
quadratic equation:3-6t+8t2.
Solution
a=8, b=-6, c=3
Maximum = 4ac-b2
4a
Maximum = (4x8x3)-(-6)2
4(8)
Maximum = (96)- 36
32
Maximum= 60
32
Maximum = 15
8
Hence maximum value is 15/8
TRY THIS………………………………..
NECTA 2003 QN.
10c
Find the maximum value of the
quadratic equation:3+30t-5t2.
No comments:
Post a Comment