Monday, 24 February 2014
A bag contains 6 red balls and 8 blue balls. Two balls are taken from the bag. What is the probability that they are both blue?
(This is a problem with replacement)
n(R) = 6, n(B) = 8, n(S) = 14
P(B) = n(B)
1st pick = 8/14
2nd pick = 8/14 as well.
P(B) = 6 x 6
P(B) = 36 = 4
Therefore Probability of drawing a blue ball is 4/49
TRY THIS ..............
A bag contains 10 purple stones and 12 blue stones. Two stones are taken from the bag. What is the probability that they are both blue?