Given the interval of 5 -16 inclusive, Find the
probability of having an even number or a prime number.
Solution
This
is a mutually exclusive event.
n(S) =
number of sample space = 12
Even
numbers(E): 6, 8, 10, 12, 14, 16 = 6
Prime
numbers(P): 5, 7, 11,13 = 4
Let P(E)=
probability of even numbers = 6/12
Let P(R)=
probability of prime numbers = 43/12
P(EnR) =
probability of having both even and prime numbers= 0/12
P(EuR) =
P(E) + P(R) - P(EnR).
P(EuR) =
6 + 4 – 0
12 12
12
P(EuR) = 10
- 0
12 12
P(EuR) = 10
= 5
12 6
Hence
probability of an even number or a prime number is 5/6.
TRY
THIS...............
Given the interval of 13 -31 inclusive, find
the probability of having an even number or a prime number.
No comments:
Post a Comment