Saturday, 17 January 2015

FUNCTIONS 2




If F(x) = log3x, Find F(1/6561)

Solution

F(x) = log3x

F(1/6561) = log3(1/6561)

F(1/6561) = log36561-1  

F(1/6561) = log3(38)-1       [6561= 3x3x3X3X3X3X3X3X3X3=38 by prime factorization]

F(1/6561) = log33(8 x -1)

F(1/6561) = log33-8

F(1/6561) = -8log33

F(1/6561) = -8 x 1

F(1/6561) = -8

Therefore F(1/6561) = -8

TRY THIS……………………….

If F(x) = log3x, Find F(1/1287)
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