Given the interval of 3 -12 inclusive, Find the
probability of having an even number or a prime number.
Solution
This is a mutually exclusive event.
n(S) =
number of sample space = 10
Even
numbers: 4,6,8,10,12 = 5
Prime
numbers: 5,7,8,11 = 4
Let P(E)=
probability of even numbers = 5/10
Let P(R)=
probability of prime numbers = 4/10
P(EnR) =
probability of having both even and prime numbers= 0/10
∴ P(EuR) =
P(E) + P(R) - P(EnR).
P(EuR) =
5 + 4 – 0
10 10
10
P(EuR) = 9
- 0
10 10
P(EuR) = 9
10
Hence
probability of an even number or a prime number is 9/10.
TRY
THIS................
Given the interval of 3 -15 inclusive, find the
probability of having an even number or a prime number.
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