CONGRUENCE OF TRIANGLES 2

Prove that <ABC = <CED in the figure below. 

Solution

AC = DC ----------- given

BC = EC ----------- given

<BAC = <EDC = 90 ------------ given.

Hence, triangle ABC = triangle CED by SAS

Hence, <ABC = <CED shown.

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Prove that <MNP = <QRP in the figure below.