If
F(x) = log3x, Find F(59049)
Solution
F(x)
= log3x
F(59049)= log3(59049)
F(59049)= log3310 [59049=
3x3x3X3X3X3X3X3X3X3=310 by prime factorization]
F(59049)= 10log33
F(59049)= 10x 1
F(59049) = 10
Therefore F(59049) = 10
TRY THIS……………………….
If
F(x) = log3x, Find F(1287)
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