SETS 1A

If n(A)= 72 , n(B)= 100 and n(AnB)=50, find n(AuB).

Solution

n(AuB) = n(A) + n(B) - n(AnB)

             = 72 + 100 – 50

             = 172– 50

             = 122

Hence n(AuB) = 122 answer

TRY THIS………….

If n(A)= 130 , n(B)= 178 and n(AnB)=96, find n(AuB).