MATHEMATICS PROBLEM SOLVER

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Saturday, 4 February 2017

ARITHMETIC PROGRESSION 1A

The 1st term of an A.P. is 76 and the common difference is 40. Find the 10th term.

Solution

A₁= 76, d = 40

A_n = A₁ + (n-1)d

A₁₀ = A₁ + (10-1)d

A₁₀ = A₁ + 9d

A₁₀ = 76 + (9x40) [ after substituting A₁= 76, d = 30 as given above]

∴ A₁₀ = 76 + 360

A₁₀ = 436

Hence the 10th term is 436.

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The 1st term of an A.P. is 60 and the common difference is 48. Find the 7th term.

MATHEMATICS PROBLEM SOLVER

Saturday, 4 February 2017

ARITHMETIC PROGRESSION 1A

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