Find a linear function f(x) with
gradient -6 which is such that f(5)=12.
Solution.
m=-6, points = [5,10] and [x, f(x)]
m = y2-y1/x2-x1
-6 = [f(x) – 10]/x-5
f(x)-10=-6(x-5) [after cross multiplying]
f(x)-10=-6x+30
f(x)=-6x+30+10
f(x)=-6x+40
A linear
function is f(x) = -6x + 40.
TRY THIS……….
Give out a linear function f(x) with
gradient -8 and f(2)=12
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