LOGARITHMS 1K

Change the following into exponential form

i) Log₇ 49 = 2

ii) Log₂ 16 = 4

iii) Log₈ 1 = 0

iv) log₅ (¹/₁₂₅) = -3

Solution

i)  log₇ 49 = 2⇔7² = 49

ii)  Log₂ 16 = 4⇔2⁴ = 16

iii)   log₈ 1 = 0⇔8⁰ = 1

iv)  log₅ (¹/₁₂₅) = -3⇔ 5^-3 = ¹/₁₂₅

TRY THIS…………….

Change the following into exponential form.

i) Log₁₁ 121 = 2

ii) Log₃ 81 = 4

iii) Log₂₆1 = 0

iv) log₄ (¹/₆₄) = -3