Wednesday, 15 February 2017

CONGRUENCE 1B


In the figure below, prove that ΔEFG and ΔGEH  are congruent. (diagram not to scale) 


Solution

GIVEN: Quadrilateral EFGH,
              EF=GH,
              <FGE=<GEH

REQUIRED TO PROVE: ΔEFG ΔEGH.
PROOF:  EG=GE           (given)
              <FGE=<GEH    (given)
               EG= GE          (common)
Hence ΔEFG ΔEGH  (By SAS)

TRY THIS…………………

In the figure below, prove that ΔSTU and ΔUSV are congruent.


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