FUNCTIONS 2

Find remainder when P(x) = x⁵ + 3x³ – x +6  is divided by Q(x)=x+3;

Solution

Let x+3 = 0

x=0-3

x = -3 

Now we substitute x=-3 in P(x).

P(x) = x⁵ + 3x³ – x +6 

P(-3) = (-3)⁵ + (-3)³ – (-3) +6 

P(-3) = -243 + (-27) – (-3) +6 

P(-3) = -243 + (-30) +6 

P(-3) = -273 +6 

P(-3) = -266

So remainder is -266

TRY THIS……………

Find remainder when P(x) = x⁵ - 3x³ – x +4  is divided by Q(x)=x-3;