Sunday, 2 April 2017

FUNCTIONS 1


If F(x) = log7x,   Find F(16807)

Solution

F(x) = log7x

F(16807)= log7(16807)

F(16807)= log77[16807= 7x7x7x7x7=75 by prime factorization]
  
F(16807)= 5log77

F(16807)= 5x 1

F(16807) = 5

Therefore F(16807) = 5

TRY THIS……………………….


If F(x) = log3x, Find F(3861)


No comments:

Post a Comment