A line passes through
(3a, 27) and (8,5a). If its slope is 4, find a.
Solution
x1=3a, y1 = 27, x2 =
8, y2 = 5a
Slope(m) =
y2 – y1
x2 – x1
4 = 5a – 27
8 – 3a
4 = 5a
– 27 [cross multiplying]
1 8 – 3a
4(8 – 3a) = 5a – 27
32 – 12a = 5a – 27
32 – 12a + 27 = 5a
32 + 27 = 12a+ 8a
60 = 20a
60 = 20a
20 20
3 = a
Hence a = 3
TRY THIS.....................................
A line passes through
(2a, 7) and (8,5a). If its slope is 2, find a.
No comments:
Post a Comment