Factorize
completely (3x-2)2 - x2
solution
= (3x-2)2
- x2
= [(3x-2)
- x][ (3x-2) + x ] --- since a2 + b2
= (a+b)(a-b) Here a is (x-2) and b
is x.
= [3x-2 -
x][ 3x-2 + x ]
= [3x-x-2][ 3x+
x - 2 ]
= [2x-2][ 4x
- 2 ]
= [2x-2][ 4x
- 2 ]
Hence (3x-2)2
- x2 = (2x-2)(4x - 2)
TRY THIS....................
Factorize
completely (4x-1)2 - x2
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