A line passes through (9a, 8) and
(8, 5a). If its slope is 2, find a.
Solution
x1=9a, y1 = 8, x2 = 8, y2 = 5a
Slope(m) = y2 –
y1
x2 – x1
2 = 5a – 8
8
– 29a
2 = 5a
– 8 [cross multiplying]
1
8 – 9a
2(8 – 9a) = 5a – 8
16 – 18a = 5a – 8
16 – 18a + 8 = 5a
16 + 8 = 5a+ 18a
24 = 23a
24 = 23a
23 23
24/23 = a
Hence
a = 24/23
TRY
THIS.................................
A line passes through (3a, 5) and
(2, 6a). If its slope is 8, find a.
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