Monday, 8 February 2016

ABSOLUTE VALUE FUNCTION 1


If f(x) = |x - 3| evaluate f(-27)

solution

f(x) = |x - 3|

f(-27) = |-27 - 3|

f(-27) = |-30| = 30 since ay number out of absolute signs is +ve.

Hence f(-27) = 30

TRY THIS..................

NECTA 1997 QN. 3b (i)

If f(x) = |x - 7| evaluate f(-27)


No comments:

Post a Comment