Factorize
completely (3x-5)2 - x2
solution
= (3x-5)2
- x2
= [(3x-5)
- x][ (3x-5) + x ] ---
since a2 + b2 = (a+b)(a-b) Here a is (x-2) and b is x.
= [3x-5 -
x][ 3x-5 + x ]
=
[3x-x-5][ 3x+ x - 5 ]
= [2x-5][
4x - 5 ]
= [2x-5][
4x - 5 ]
Hence (2x-5)2 - x2 =
(2x-2)(4x - 5)
TRY
THIS....................
Factorize
completely (6x-1)2 - x2
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