Evaluate Log2(256 x 32).
Solution
= Log2(256 x 32)
= Log2256 + Log232
(applying the product rule)
= Log228
+ Log225 (
256= 28 and 32=25 )
= 8Log22 + 5Log22
( remember Logaac = cLogaa )
= (8 x 1) + (5 x 1)
( remember Logaa
= 1 )
= 8 + 5
= 13
Hence Log2(128 x 32) =
12
TRY
THIS...............
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