Wednesday, 1 April 2015

LOGARITHMS 2


Evaluate Log2(256 x 32).

Solution

= Log2(256 x 32)

= Log2256 +  Log232          (applying the product rule)

= Log228 +  Log225             ( 256= 28 and 32=25 )

= 8Log22 +  5Log22       ( remember  Logaac = cLogaa )

= (8 x 1) +  (5 x 1)          ( remember  Logaa = 1 )

= 8 + 5

= 13


Hence Log2(128 x 32) = 12 

TRY THIS...............

Evaluate Log2(256 x 128).


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