Saturday, 3 August 2013

QUADRATIC-5


If zx2 + 12x + 4 = 0 is a perfect square, find the value of z .

Solution

In zx2 + 12x + 4 = 0;   a=z, b=12 and c=4.


For the perfect square, b2 = 4ac


(12)2 = 4 x z x 4


144 = 16z


144 =  16z
 16       16


9 = z



Hence the value of z is 9



No comments:

Post a Comment