Saturday, 3 August 2013

CO-ORDINATE GEOMETRY-4


Find the slope of a line which passes through (8, 6) and (-11,-3)

Solution

x1 = 8,  y1 =6,  x2 =-11,  y2 = -3

m = y2 –y1
       x2 – x1

m =    -3 –6
         -11 –8

m =     - 9
          - 19

m =  9
       19


Hence the slope is 9/19

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