The 1st term of an A.P. is 10 and the common difference is 58.
Find the 12th term.
Solution
A1= 10, d = 58
An = A1 + (n-1)d [ formula for n terms ]
A12 = A1 + (12-1)d
A12 = A1 + 11d [
formula for 12 terms ]
A12 = 10 + (11 x 58)
A12 = 10 + 638
A12 = 648
Hence the
12th term is 648.
No comments:
Post a Comment