If n(A)= 85 , n(B)= 96 and n(AuB)= 129, find n(AnB).
Solution
n(AuB) = n(A) + n(B) - n(AnB)
129 = 85 + 96 - n(AnB)
129 = 181 - n(AnB)
129 - 181 = - n(AnB)
-58 = -n(AnB)
n(AnB) = 58 [after dividing by -1 both
sides]
Hence n(AnB) = 58 answer
TRY THIS………….
If n(A)= 91 , n(B)= 94 and n(AuB)= 127,
find n(AnB).
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